Golang : Trim everything onward after a word
Putting this simple example here for my own future reference. Basically, the problem that I'm trying to solve is to get rid of the rest from from a sentence after a word.
For example, I want to get rid of everything from "abc" onward. How to do that?
BEFORE :
s := "123123123123123456abc789123123123123"
AFTER :
s := "123123123123123456"
The solution is to use strings.LastIndex()
to get the position of abc
and then only capture the part before the position.
package main
import (
"fmt"
"strings"
)
func main() {
s := "123123123123123456abc789123123123123"
position := strings.LastIndex(s, "abc")
fmt.Println(s[:position])
}
Hope this help!
Happy computing!
See also : Golang : package is not in GOROOT during compilation
By Adam Ng
IF you gain some knowledge or the information here solved your programming problem. Please consider donating to the less fortunate or some charities that you like. Apart from donation, planting trees, volunteering or reducing your carbon footprint will be great too.
Advertisement
Tutorials
+17.3k Golang : Linked list example
+9.5k Golang : Copy map(hash table) example
+20k Swift : Convert (cast) Int to int32 or Uint32
+10.5k Golang : Flip coin example
+7.6k Golang : Lock executable to a specific machine with unique hash of the machine
+36.5k Golang : Display float in 2 decimal points and rounding up or down
+32.8k Golang : How to check if a date is within certain range?
+12.3k Golang : Search and extract certain XML data example
+5.7k Golang : Error handling methods
+10.1k Golang : Text file editor (accept input from screen and save to file)
+10k Golang : Identifying Golang HTTP client request
+25.1k Golang : Generate MD5 checksum of a file