Golang : Trim everything onward after a word
Putting this simple example here for my own future reference. Basically, the problem that I'm trying to solve is to get rid of the rest from from a sentence after a word.
For example, I want to get rid of everything from "abc" onward. How to do that?
BEFORE :
s := "123123123123123456abc789123123123123"
AFTER :
s := "123123123123123456"
The solution is to use strings.LastIndex()
to get the position of abc
and then only capture the part before the position.
package main
import (
"fmt"
"strings"
)
func main() {
s := "123123123123123456abc789123123123123"
position := strings.LastIndex(s, "abc")
fmt.Println(s[:position])
}
Hope this help!
Happy computing!
See also : Golang : package is not in GOROOT during compilation
By Adam Ng
IF you gain some knowledge or the information here solved your programming problem. Please consider donating to the less fortunate or some charities that you like. Apart from donation, planting trees, volunteering or reducing your carbon footprint will be great too.
Advertisement
Tutorials
+16.1k Golang : Update database with GORM example
+9.7k Golang : Extract or copy items from map based on value
+17.3k Golang : Capture stdout of a child process and act according to the result
+5.8k Golang : Shortening import identifier
+12.7k Golang : Arithmetic operation with numerical slices or arrays example
+17.4k Golang : When to use init() function?
+24.8k Golang : How to validate URL the right way
+21.8k Golang : How to read float value from standard input ?
+18.8k Golang : Get download file size
+13.3k Golang : How to get a user home directory path?
+13.9k Golang : Get user input until a command or receive a word to stop
+15.2k Golang : Search folders for file recursively with wildcard support