Golang : Trim everything onward after a word
Putting this simple example here for my own future reference. Basically, the problem that I'm trying to solve is to get rid of the rest from from a sentence after a word.
For example, I want to get rid of everything from "abc" onward. How to do that?
BEFORE :
s := "123123123123123456abc789123123123123"
AFTER :
s := "123123123123123456"
The solution is to use strings.LastIndex()
to get the position of abc
and then only capture the part before the position.
package main
import (
"fmt"
"strings"
)
func main() {
s := "123123123123123456abc789123123123123"
position := strings.LastIndex(s, "abc")
fmt.Println(s[:position])
}
Hope this help!
Happy computing!
See also : Golang : package is not in GOROOT during compilation
By Adam Ng
IF you gain some knowledge or the information here solved your programming problem. Please consider donating to the less fortunate or some charities that you like. Apart from donation, planting trees, volunteering or reducing your carbon footprint will be great too.
Advertisement
Tutorials
+14.7k Golang : Check if a string contains multiple sub-strings in []string?
+3.6k Linux/MacOSX : How to symlink a file?
+7.5k Yum Error: no such table: packages
+12.2k Golang : unknown escape sequence error
+19.2k Golang : GORM create record or insert new record into database example
+5.3k Golang : Totalize or add-up an array or slice example
+7.5k Golang : HTTP Routing with Goji example
+37.4k Golang : UDP client server read write example
+5.2k Nginx : Password protect a directory/folder
+7.1k Golang : Another camera capture GUI application with GTK and OpenCV
+7.5k Golang : Build and compile multiple source files
+10.1k Golang : Convert(cast) bigint to string