Golang : Repeat a character by multiple of x factor



Tags : golang python strings-repeat multiply-letters

In Python, it is pretty easy to repeat some characters inside a string. All you need to do is to multiply the letter with an integer value and the letter will be multiplied/repeated by x number of times For example: str = ''.join(['a' * 1, 'b' * 1, 'c' * 2, 'd' * 3, 'e' * 2, 'f' * 4, \ 'g' * 5, 'h' * 6, 'i' * 3, 'j' * 7, 'k' * 8, 'l' * 9, 'm' * 10, \ 'n' * 11, 'o' * 4, 'p' * 12, 'q' * 13, 'r' * 14, 's' * 15, \ 't' * 16, 'u' * 5, 'w' * 17, 'y' * 18, 'z' * 19]) will produce: abccdddeeffffggggghhhhhhiiijjjjjjjkkkkkkkklllllllllmmmmmmmmmmnnnnnnnnnnnoo ooppppppppppppqqqqqqqqqqqqqrrrrrrrrrrrrrrsssssssssssssssttttttttttttttttuuuuuw wwwwwwwwwwwwwwwwyyyyyyyyyyyyyyyyyyzzzzzzzzzzzzzzzzzzz However, it is not permissible to multiply a letter with integer in Golang. Doing so will generate error such as invalid operation: "join" * 2 (mismatched types string and int). To create multiple instances/repeatition of a letter in Golang, you will have to use the strings.Repeat() function. Example: package main import ( "fmt" "strings" ) func main() { str := []string{"a", "b", "c", "d", "e" fmt.Println(strings.Join(str, " ")) // Python way of repeating string by multiple of x will // not work here //str2 := []string{"a" * 2, "b", "c", "d", "e" // Golang's way of multiplying a string by x factor str2 := []string{strings.Repeat("a", 2), "b", "c", "d", "e" fmt.Println(strings.Join(str2, " ")) a2 := strings.Repeat("a", 2) b3 := strings.Repeat("b", 3) c4 := strings.Repeat("c", 4) d5 := strings.Repeat("d", 5) e9 := strings.Repeat("e", 9) str3 := []string{a2, b3, c4, d5, e9 fmt.Println(strings.Join(str3, " ")) Output: a b c d e aa b c d e aa bbb cccc ddddd eeeeeeeee References: https://www.socketloop.com/tutorials/golang-how-to-join-strings


Tags : golang python strings-repeat multiply-letters

By Adam Ng

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