Golang : How to execute code at certain day, hour and minute?

Problem:

You want to execute certain code at a particular day, hour and minute only. Such as Monday, 10:30 AM. How to do that?

Solution:

Normally, this should be solved with cron or scheduler utility. However, no harm knowing how to do it at code level.

You will need time.Now(), time.Clock() and time.Weekday() to retrieve the current day, hour, minute and second to determine if the condition is right to execute your code.

Here you go!

 package main

 import (
 "fmt"
 "os"
 "time"
 )

 func main() {
 now := time.Now()

 day := now.Weekday()


 hr, min, sec := now.Clock()

 // only execute code on Monday 10:30 AM

 fmt.Println("Code will only execute on every Monday, 10:30 AM")

 // ignore second for now
 if day == 1 && hr == 10 && min == 30 {
 fmt.Println("Executing this portion of code to cure Monday blues...")
 } else {

 fmt.Printf("However, it is [%v], [%d]hour : [%d]minutes : [%d] seconds now.\n", day.String(), hr, min, sec)
 fmt.Println("So, go back to work!")
 os.Exit(0)
 }

 }

If the program runs on Monday 10:30AM, the output will be:

$ ./particularday

Code will only execute on every Monday, 10:30 AM

Executing this portion of code to cure Monday blues...

else the output will be:

Code will only execute on every Monday, 10:30 AM

However, it is [Monday], [10]hour : [46]minutes : [51] seconds now.

So, go back to work!

References:

https://www.socketloop.com/references/golang-time-time-clock-function-example

https://www.socketloop.com/tutorials/golang-how-to-get-year-month-and-day