Golang : Extract part of string with regular expression



Tags : golang regular-expression regexp extract-string

Below is a simple example of how to extract a specific part of a string with the help of regular expression. For example, we are interested in extracting the part that starts with #$ from couple of strings such as

#$q4 revenue for 2017

revenue #$q2 for 2017

2017 revenue is #$q3

Here you go!


 package main

 import (
  "fmt"
  "regexp"
 )

 func main() {
  str1 := "#$q4 revenue for 2017"

  str2 := "revenue #$q2 for 2017"

  str3 := "2017 revenue is #$q3"

  // regular expression pattern
  regE := regexp.MustCompile("\\#\\$q[1-4]")

  fmt.Println(regE.FindAllString(str1, -1))
  fmt.Println(regE.FindAllString(str2, -1))
  fmt.Println(regE.FindAllString(str3, -1))

  str4 := []string{str3, str1, str2}

  for k, v := range str4 {
 fmt.Println(k, regE.FindAllString(v, -1))
  }

 }

Output:

[#$q4]

[#$q2]

[#$q3]

0 [#$q3]

1 [#$q4]

2 [#$q2]



Tags : golang regular-expression regexp extract-string

By Adam Ng

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