Golang : Shuffle array of list
Continue from previous tutorial on how to shuffle an array of strings, to shuffle array of list is not really straight forward, but it can be done easily with rand.Perm()
function. Use this code example to shuffle an array of list.
package main
import (
"fmt"
"math/rand"
"time"
)
func shuffleList(start, end int) []int {
if end < start {
start, end = end, start
}
length := end - start
rand.Seed(time.Now().UTC().UnixNano())
list := rand.Perm(length)
for index, _ := range list {
list[index] += start
}
return list
}
func main() {
mapList := make([]map[int]int, 3)
mapList[0] = map[int]int{1: 1}
mapList[1] = map[int]int{2: 2}
mapList[2] = map[int]int{3: 3}
shuffled := shuffleList(0, len(mapList))
fmt.Printf("Original order : %v\n", mapList)
fmt.Printf("Shuffled order : %v\n", shuffled)
}
Sample output :
Original order : [map[1:1] map[2:2] map[3:3]]
Shuffled order : [1 0 2]
See also : Golang : Shuffle strings array
By Adam Ng
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