Golang : Shuffle array of list

Continue from previous tutorial on how to shuffle an array of strings, to shuffle array of list is not really straight forward, but it can be done easily with rand.Perm() function. Use this code example to shuffle an array of list.

 package main

 import (

 func shuffleList(start, end int) []int {
 if end < start {
 start, end = end, start

 length := end - start

 list := rand.Perm(length)
 for index, _ := range list {
 list[index] += start
 return list

 func main() {

 mapList := make([]map[int]int, 3)

 mapList[0] = map[int]int{1: 1}

 mapList[1] = map[int]int{2: 2}

 mapList[2] = map[int]int{3: 3}

 shuffled := shuffleList(0, len(mapList))

 fmt.Printf("Original order  :  %v\n", mapList)

 fmt.Printf("Shuffled order  :  %v\n", shuffled)


Sample output :

Original order : [map[1:1] map[2:2] map[3:3]]

Shuffled order : [1 0 2]

  See also : Golang : Shuffle strings array

By Adam Ng

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