Golang : Shuffle array of list



Tags : golang shuffle array slice list map

Continue from previous tutorial on how to shuffle an array of strings, to shuffle array of list is not really straight forward, but it can be done easily with rand.Perm() function. Use this code example to shuffle an array of list.

 package main

 import (
 "fmt"
 "math/rand"
 "time"
 )

 func shuffleList(start, end int) []int {
 if end < start {
 start, end = end, start
 }

 length := end - start
 rand.Seed(time.Now().UTC().UnixNano())

 list := rand.Perm(length)
 for index, _ := range list {
 list[index] += start
 }
 return list
 }

 func main() {

 mapList := make([]map[int]int, 3)

 mapList[0] = map[int]int{1: 1}

 mapList[1] = map[int]int{2: 2}

 mapList[2] = map[int]int{3: 3}

 shuffled := shuffleList(0, len(mapList))

 fmt.Printf("Original order  :  %v\n", mapList)

 fmt.Printf("Shuffled order  :  %v\n", shuffled)

 }

Sample output :

Original order : [map[1:1] map[2:2] map[3:3]]

Shuffled order : [1 0 2]

  See also : Golang : Shuffle strings array



Tags : golang shuffle array slice list map

By Adam Ng

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