Golang : How to execute code at certain day, hour and minute?
Problem:
You want to execute certain code at a particular day, hour and minute only. Such as Monday, 10:30 AM. How to do that?
Solution:
Normally, this should be solved with cron
or scheduler
utility. However, no harm knowing how to do it at code level.
You will need time.Now()
, time.Clock()
and time.Weekday()
to retrieve the current day, hour, minute and second to determine if the condition is right to execute your code.
Here you go!
package main
import (
"fmt"
"os"
"time"
)
func main() {
now := time.Now()
day := now.Weekday()
hr, min, sec := now.Clock()
// only execute code on Monday 10:30 AM
fmt.Println("Code will only execute on every Monday, 10:30 AM")
// ignore second for now
if day == 1 && hr == 10 && min == 30 {
fmt.Println("Executing this portion of code to cure Monday blues...")
} else {
fmt.Printf("However, it is [%v], [%d]hour : [%d]minutes : [%d] seconds now.\n", day.String(), hr, min, sec)
fmt.Println("So, go back to work!")
os.Exit(0)
}
}
If the program runs on Monday 10:30AM, the output will be:
$ ./particularday
Code will only execute on every Monday, 10:30 AM
Executing this portion of code to cure Monday blues...
else the output will be:
Code will only execute on every Monday, 10:30 AM
However, it is [Monday], [10]hour : [46]minutes : [51] seconds now.
So, go back to work!
References:
https://www.socketloop.com/references/golang-time-time-clock-function-example
https://www.socketloop.com/tutorials/golang-how-to-get-year-month-and-day
See also : Golang : How to get year, month and day?
By Adam Ng
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