Golang : Get host name or domain name from IP address

Thought this tutorial could be a good compliment to previous tutorial on how to find network of an IP address. Basically, what this small Golang program does is to scan and try to map a given IP address to its equivalent domain/host name... a reverse of translating domain name to IP addresses.

Here you go :

 package main

 import (
 "fmt"
 "net"
 "os"
 "strconv"
 "strings"
 "time"
 )

 func getHostName(host chan string, ipAddress string, n int) {
 ip := ipAddress + strconv.Itoa(n)

 if addr, err := net.LookupAddr(ip); err == nil {
 host <- ip + " -" + addr[0]
 } else {
 host <- "err " + err.Error()
 }
 }

 func main() {
 if len(os.Args) != 2 {
 fmt.Fprintf(os.Stderr, "Usage: %s IP-address\n", os.Args[0])
 os.Exit(1)
 }

 ipAddr := os.Args[1]

 segments := strings.SplitAfter(ipAddr, ".")

 ipAddress := segments[0] + segments[1] + segments[2]

 haveHost := make(chan string)

 max := 55

 for counter := 0; counter < max; counter++ {
 go getHostName(haveHost, ipAddress, counter)
 }

 count := 0

 timeOut := time.After(5 * time.Second)

 lookups:
 for {

 select {

 case host := <-haveHost:
 fmt.Println("host :" + host)
 case <-timeOut:
 fmt.Println("time out")
 break lookups
 }
 count++

 if count == max {
 break
 }

 }

 fmt.Println("Network scanned")

 }

Sample output :

$ ./netinterfaces 54.255.183.119

host :54.255.183.0 -ec2-54-255-183-0.ap-southeast-1.compute.amazonaws.com.

host :54.255.183.5 -ec2-54-255-183-5.ap-southeast-1.compute.amazonaws.com.

host :54.255.183.26 -ec2-54-255-183-26.ap-southeast-1.compute.amazonaws.com.

host :54.255.183.28 -ec2-54-255-183-28.ap-southeast-1.compute.amazonaws.com.

host :54.255.183.44 -ec2-54-255-183-44.ap-southeast-1.compute.amazonaws.com.

host :54.255.183.2 -ec2-54-255-183-2.ap-southeast-1.compute.amazonaws.com.

References :

https://www.socketloop.com/tutorials/golang-find-network-of-an-ip-address

http://golang.org/pkg/net/#LookupAddr