Golang : Generate human readable password



Tags : golang human-readable password random-string

Got a friend who works in the banking sector and she needs to password generator that will generate a password that is easy to be read over the phone by a text-to-voice software and must be "human-friendly" for phone banking purpose. "Human-friendly" in terms of easier to write down and remember.

For example, a password such as "hello123pass" is easier to read and remember than "e1jda87dn22".

Below is a code example that I've helped to create for her that might be useful to you.

For best result, keep the number of alphabets to 6 and digits to 2, it should be practical and random enough. Anything beyond that will be hard to read and remember.

If you plan to add some runes into the password, see https://www.socketloop.com/tutorials/golang-random-rune-generator

Here you go!


 package main

 import (
 "fmt"
 "math/rand"
 "time"
 )

 //var vowels = []rune{'a', 'e', 'i', 'o', 'u'}
 //var consonants = []rune{'b', 'c', 'd', 'f', 'g', 'h', 'j', 'k', 'l', 'm', 'n','p', 'q', 'r', 's', 't', 'v', 'w', 'x', 'y', 'z'}

 func humanReadablePassword(alphabetSize, numberSize int) string {

 vowels := "aeiou"
 consonants := "bcdfghjklmnpqrstvwxyz"
 digits := "0123456789"

 prefixSize := alphabetSize / 2
 if alphabetSize%2 != 0 {
 prefixSize = int(alphabetSize/2) + 1
 }
 suffixSize := alphabetSize - prefixSize

 var prefixPart = make([]byte, prefixSize)

 for i := 0; i <= prefixSize-1; i++ {
 if i%2 == 0 {
 // use consonants
 prefixPart[i] = consonants[rand.Intn(len(consonants)-1)]
 } else {
 // use vowels
 prefixPart[i] = vowels[rand.Intn(len(vowels)-1)]
 }
 }

 var midPart = make([]byte, numberSize)

 // use digits
 for k, _ := range midPart {
 midPart[k] = digits[rand.Intn(len(digits))]
 }

 var suffixPart = make([]byte, suffixSize)

 for i := 0; i <= suffixSize-1; i++ {
 if i%2 == 0 {
 // use consonants
 suffixPart[i] = consonants[rand.Intn(len(consonants)-1)]
 } else {
 // use vowels
 suffixPart[i] = vowels[rand.Intn(len(vowels)-1)]
 }
 }

 return string(prefixPart) + string(midPart) + string(suffixPart)
 }

 func main() {
 rand.Seed(time.Now().UnixNano())
 fmt.Println("6 alphabets with 2 digits : ", humanReadablePassword(6, 2)) // best option
 fmt.Println("3 alphabets with 8 digits : ", humanReadablePassword(3, 8))
 fmt.Println("9 alphabets with 9 digits : ", humanReadablePassword(9, 9))

 }

Output:

6 alphabets with 2 digits : hax32diy

3 alphabets with 8 digits : me80029642k

9 alphabets with 9 digits : tewet321311617poqe

References:

https://www.socketloop.com/tutorials/golang-random-rune-generator

https://www.socketloop.com/tutorials/golang-how-to-generate-random-string

https://en.wikipedia.org/wiki/Consonant

  See also : Golang : Random Rune generator



Tags : golang human-readable password random-string

By Adam Ng

IF you gain some knowledge or the information here solved your programming problem. Please consider donating to the less fortunate or some charities that you like. Apart from donation, planting trees, volunteering or reducing your carbon footprint will be great too.


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