Golang : Convert(cast) string to uint8 type and back to string
Problem :
You have a variable of type string and you want to convert/type cast it to uint8 type.
Solution :
If you plan to convert a single character, then type cast it with uint8()
function. If the string is couple of characters, use []uint8()
instead.
For example :
package main
import (
"fmt"
"reflect"
)
var str string = "this is a string"
func main() {
fmt.Printf("The value of test is %s \n", str)
fmt.Printf("The type of test is %v \n", reflect.TypeOf(str))
newStr := []uint8(str)
fmt.Printf("The value of newStr is %s \n", newStr)
fmt.Printf("The type of newStr is %v \n", reflect.TypeOf(newStr))
// convert back to string
backToStr := string([]byte(newStr[:]))
fmt.Println(backToStr)
fmt.Printf("The value of backToStr is [%s] \n", backToStr)
fmt.Printf("The type of backToStr is %v \n", reflect.TypeOf(backToStr))
}
Output :
The value of test is this is a string
The type of test is string
The value of newStr is this is a string
The type of newStr is []uint8
this is a string
The value of backToStr is [this is a string]
The type of backToStr is string
By Adam Ng
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