Golang : Repeat a character by multiple of x factor

In Python, it is pretty easy to repeat some characters inside a string. All you need to do is to multiply the letter with an integer value and the letter will be multiplied/repeated by x number of times

For example:

 str = ''.join(['a' * 1, 'b' * 1, 'c' * 2, 'd' * 3, 'e' * 2, 'f' * 4, \
 'g' * 5, 'h' * 6, 'i' * 3, 'j' * 7, 'k' * 8, 'l' * 9, 'm' * 10, \
 'n' * 11, 'o' * 4, 'p' * 12, 'q' * 13, 'r' * 14, 's' * 15, \
 't' * 16, 'u' * 5, 'w' * 17, 'y' * 18, 'z' * 19])

will produce:

 abccdddeeffffggggghhhhhhiiijjjjjjjkkkkkkkklllllllllmmmmmmmmmmnnnnnnnnnnnoo
 ooppppppppppppqqqqqqqqqqqqqrrrrrrrrrrrrrrsssssssssssssssttttttttttttttttuuuuuw
 wwwwwwwwwwwwwwwwyyyyyyyyyyyyyyyyyyzzzzzzzzzzzzzzzzzzz

However, it is not permissible to multiply a letter with integer in Golang. Doing so will generate error such as invalid operation: "join" * 2 (mismatched types string and int).

To create multiple instances/repeatition of a letter in Golang, you will have to use the strings.Repeat() function.

Example:

 package main

 import (
 "fmt"
 "strings"
 )

 func main() {
 str := []string{"a", "b", "c", "d", "e"}

 fmt.Println(strings.Join(str, " "))

 // Python way of repeating string by multiple of x will
 // not work here
 //str2 := []string{"a" * 2, "b", "c", "d", "e"}

 // Golang's way of multiplying a string by x factor
 str2 := []string{strings.Repeat("a", 2), "b", "c", "d", "e"}

 fmt.Println(strings.Join(str2, " "))

 a2 := strings.Repeat("a", 2)
 b3 := strings.Repeat("b", 3)
 c4 := strings.Repeat("c", 4)
 d5 := strings.Repeat("d", 5)
 e9 := strings.Repeat("e", 9)
 str3 := []string{a2, b3, c4, d5, e9}

 fmt.Println(strings.Join(str3, " "))
 } 

Output:

a b c d e

aa b c d e

aa bbb cccc ddddd eeeeeeeee

References:

https://www.socketloop.com/tutorials/golang-how-to-join-strings